Question 340424: The average of the salaries of Kelly, Renee and Nina is 20,000 a year. If Kelly earns 4000 less than Renee and Nina's salary is two-thirds of Renee's salary, find the salary of each person.
I've tried setting up as follows;
Let R = Renee
Let R - 4000 = Kelly
Let 2/3 * R = Nina
R + ( R - 4000 ) + 2/3 * R = 20,000
It's not working out for me though. Anyone have any thoughts?
Found 4 solutions by Fombitz, jim_thompson5910, alanc, solver91311:
Answer by Fombitz(32388)   (Show Source):
Answer by jim_thompson5910(35256)  (Show Source):
Answer by alanc(27)  (Show Source):
You can put this solution on YOUR website! Your last equation is wrong. you don't sum the salaries to get the average. it should be divided by 3.
so
[R + ( R - 4000 ) + 2/3 * R ]/3 = 20,000
[R + R + 2/3 * R - 4000]/3 = [8R/3 - 4000]/3 = [8R/3 - 4000]/3 = 20000
[8R/3 - 4000] = 60000
64000 = 8R/3
R = 64000* 3 /8 = 8000* 3 = 24000
Rene makes 24,000
Kelly makes 20,000
Nina makes 16,000
Answer by solver91311(24713)  (Show Source):
|
|
|
