SOLUTION: 2. Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 mi
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: 2. Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 mi
Log On
Question 340392: 2. Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
A. 2 hours
B. 4 ½ hours
C. 5 ¾ hours
D. 6 hours
E. 7 ½ hours Answer by solver91311(24713) (Show Source):
The first cyclist, going 6 mph, will travel 18 miles during the 3 hour head start. Once the second cyclist gets going at 10 mph, 6 of those mph will be used just to keep up with the first guy, and the remaining 4 mph will be used to catch up. The question becomes: How long does it take to travel 18 miles at 4 miles per hour?
John
My calculator said it, I believe it, that settles it
