SOLUTION: Find three consecutive even integers such that 6 times the sum of the first and the third is 8 less than 14 times the second. I do not understand how to solve this problem.

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Question 340390: Find three consecutive even integers such that 6 times the sum of the first and the third is 8 less than 14 times the second.


I do not understand how to solve this problem.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Three consecutive even integers would be N, N%2B2, and N%2B4.
Find three consecutive even integers such that
"6 times the sum of the first and the third""6%28N%2B%28N%2B4%29%29=6%282N%2B4%29=12N%2B24
"is" translates to "="
"8 less than 14 times the second":14%2A%28N%2B2%29-8=14N%2B28-8=14N%2B20
.
.
.
12N%2B24=14N%2B20
Solve for N.
Then find N%2B2 and N%2B4.