Question 340284: OK....need help been trying for the last hour.. still can't get it.
Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.
If an object is propelled upward from ground level with an initial velocity of 224 feet per second, its height h in feet t seconds later is given by the equation h = 224t - 16t2. After how many seconds does the object hit the ground?
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Given:
h = 224t - 16t^2
where
h is height in feet
t is time in seconds
.
To determine when the object hit the ground,
set h to zero (because zero is when the object is on the ground) and solve for t:
h = 224t - 16t^2
0 = 224t - 16t^2
0 = 14t - t^2
factoring the right side:
0 = t(14 - t)
setting each term on the right to zero we get:
t = {0, 14}
.
t=0 is when the object just started its flight
So,
t = 14 seconds (solution)
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