SOLUTION: 3(2i+3)(1+3i)
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Question 340228
:
3(2i+3)(1+3i)
Found 2 solutions by
nyc_function, stanbon
:
Answer by
nyc_function(2741)
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3(2i+3)(1+3i) =
NOTE: i^2 = -1
(6i + 9)(3i + 1) =
18i^2 + 6i + 27i + 9 =
18(-1) + 33i + 9 =
-18 + 33i + 9 =
-9 + 33i
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Answer by
stanbon(75887)
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3(2i+3)(1+3i)
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= 3[2i-6+3+9i]
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= 3[-3+11i]
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= -9+33i
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Cheers,
Stan H.