SOLUTION: The angular velocity of a merry-go-round is 35 radians/minute. If the diameter is 38 feet, find the linear velocity of a person standing on the very edge of the merry-go-round.

Algebra ->  Trigonometry-basics -> SOLUTION: The angular velocity of a merry-go-round is 35 radians/minute. If the diameter is 38 feet, find the linear velocity of a person standing on the very edge of the merry-go-round.      Log On


   

Question 34015: The angular velocity of a merry-go-round is 35 radians/minute. If the diameter is 38 feet, find the linear velocity of a person standing on the very edge of the merry-go-round.
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
angular velocity (w)=35 radians/min=35/60 rad/second=0.5833 rad/s
diameter=38 feet
hence radius (r)=19 feet
velocity?


v%2Fr=w
v=w%2Ar
v=0.5833(19)=11.0833
=11.1 feet/s(rounding off)


-xC