SOLUTION: solve this triangle: a=32.0 b=40.0 C=71 degrees 45'
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Question 34007
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solve this triangle: a=32.0 b=40.0 C=71 degrees 45'
Answer by
venugopalramana(3286)
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C^2=A^2+B^2-2ABCOS ©
4561.159499
67.53857416
C/SIN©=B/SIN(B)
SIN(B)=BSIN©/C
0.562345411
ANGLE (B)= 34.25
ANGLE A =180-71.75-34.25=72