SOLUTION: What quantity x of a 80 % acid solution must be mixed with a 15 % solution to produce 600 mL of a 40 % solution?

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Question 339946: What quantity x of a 80 % acid solution must be mixed with a 15 % solution to produce 600 mL of a 40 % solution?
Found 2 solutions by nyc_function, checkley77:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Here is your equation:
first mixture + second mixture = total mixture
0.80x + 0.15 = 0.40(x + 600)
Can you take it form here?

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.80X+.15(600-X)=.40*600
.80X+90-.15X=240
.65X=240-90
.65X=150
X=150/.65
X=230.77 ml. of 80% mixture is used.
Proof:
,80*230.77+.15(600-230.77)=.4*600
184.62+.15(369.23)=240
184.62+55.38=240
240=240