Question 339652: john is 6 years older than jill 5 years ago john was 3 times as old as jill was then, form equation in x and solve it to find what age jill is now
Found 2 solutions by nyc_function, MathTherapy:
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! John's age now = x + 6
Jill's age now = x
John's age 5 years ago = (x + 6) - 5
Jill's age 5 years ago = x - 5
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(x + 6) - 5 = 3(x - 5)
x - 1 = 3x - 15
x - 3x = -15 + 1
-2x = -14
x = -14/-2
x = 7
Jill is 7 year old.
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Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website! john is 6 years older than jill 5 years ago john was 3 times as old as jill was then, form equation in x and solve it to find what age jill is now
Let Jill's and John's current ages be  and  , respectively
Since john is currently 6 years older than jill, then we'll have:
 , or,  ____ eq(i)
And, since 5 years ago john was 3 times as old as jill was then, then we'll also get:
 , or,  ___ eq (ii)
 ______ eq(i)
___ eq (ii)
 __ Subtracting eq (ii) from eq (i)
 ____ 
Therefore, or Jill's current age =  years.
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