SOLUTION: The perimeter of a college athletic field is 92 meters and the length is 16 m more than the width. Find the length and width. What is the width?

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Question 339560: The perimeter of a college athletic field is 92 meters and the length is 16 m more than the width. Find the length and width. What is the width?
Found 2 solutions by sammy95, jim_thompson5910:
Answer by sammy95(1) About Me  (Show Source):
You can put this solution on YOUR website!
92 (the length)- (minus) 16 for the width =
the width is 76

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint: The formula for the perimeter of a rectangle is P=2L%2B2W where 'P' is the perimeter of the rectangle, L is the length, and W is the width.

Since "The perimeter of a college athletic field is 92 meters and the length is 16 m more than the width", we know that P=92 and L=W%2B16. Plug this info into the formula above to get 92=2%28W%2B16%29%2B2W


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Jim