SOLUTION: I've tried many times to find the answer... and I've also never had a real big thing for math that's why I'm in summer school right now... If I could get any help at all it would

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I've tried many times to find the answer... and I've also never had a real big thing for math that's why I'm in summer school right now... If I could get any help at all it would       Log On


   



Question 3390: I've tried many times to find the answer... and I've also never had a real big thing for math that's why I'm in summer school right now... If I could get any help at all it would be great, and maybe a brief x-pla. on how it's to be done
"A theater sells children's tickets for $4 and adult tickets for $7. One night 575 tickets worth $3575 were sold.
How many adults and children bought tickets"
Thanks Many
Matt McIvor

Found 2 solutions by pannalal, longjonsilver:
Answer by pannalal(9) About Me  (Show Source):
You can put this solution on YOUR website!
It is a very simple problem.
Assume, tickets were sold to x children and y adults.
As the total number of tickets sold were 575, so x%2By=575 ...(1)
The worth of tickets was $3575, so 4x+%2B+7y+=+3575 ... (2)
On Multiplying Eq(1) by 4 and subtracting from Eq(2):
3y+=+1275
So, y+=+425
Now, from Eq(1) x = 150
So, there were 150 children and 425 adults.

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
questions like this...you need to investigate th eenglish and try to convert it to maths. There will be 2 things you do not know, so you need 2 (or more) equations to find them.

I have written Lessons on this site on Linear Equations and solving them simultaneously, so look at those to help you understand that bit...first the 2 equations:

1. Define the 2 things you are asked for:
Let x = number of child tickets
Let y = number of adult tickets.

2 Find the 2 equations:
a. we know the total number of tickets sold one night = 575, so x+y=575 --eqn1

b. each child ticket = $4:
if we sold 1, that would be 4*1
if we sold 2, that would be 4*2
if we sold 5, that would be 4*5
so, if we sold x, that would be a total cost of 4*x... or 4x

Similarly, for the adult tickets, their total cost = 7y

And we know that the total cost of all the tickets was $3575, so 4x+7y = 3575 --eqn2.

Now you have the 2 equations, look at my lessons to find out how to solve them.

Good luck.

jon.