SOLUTION: Express as a sum, difference, and product of logarithms, without using exponents. log[b]√((m^2p^4)/(n^2b^9)) I am at a loss, I have no clue on how to do this. Thank you i

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Express as a sum, difference, and product of logarithms, without using exponents. log[b]√((m^2p^4)/(n^2b^9)) I am at a loss, I have no clue on how to do this. Thank you i      Log On


   

Question 338749: Express as a sum, difference, and product of logarithms, without using exponents.
log[b]√((m^2p^4)/(n^2b^9))
I am at a loss, I have no clue on how to do this. Thank you in advance and GOD Bless!
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Express as a sum, difference, and product of logarithms, without using exponents.
log[b]√((m^2p^4)/(n^2b^9))
I am at a loss, I have no clue on how to do this. Thank you in advance and GOD Bless!
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Is it log%28b%2Csqrt%28m%5E2p%5E4%2Fn%5E2b%5E9%29%29 ??
If so,
= log%28b%2Csqrt%28bm%5E2p%5E4%2Fn%5E2b%5E10%29%29
= log%28b%2Csqrt%28m%5E2p%5E4%2Fn%5E2b%5E10%29%2Asqrt%28b%29%29
= log%28b%2Cmp%5E2%2Fnb%5E5%29%2Asqrt%28b%29%29
= %28log%28m%29+%2B+2log%28b%29+-+log%28n%29+-+5log%28b%29%29%2A%281%2F2%29log%28b%29 all logs base b
= %28log%28m%29+%2B+2+-+log%28n%29+-+5%29%2A%281%2F2%29 since log%28b%2Cb%29+=+1
= log(m)/2 - log(n)/2 - 3/2
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PS To which god do you refer?