Question 33872: I have constructed a pentagon with a base of 529.2 ft. The other sides follow clockwise in this order: 57.6 ft, 248 ft, 323.4 ft, and 48.5 ft. How do I find the measure of a perpendicular drawn from the base to the opposite vertex?
Base = 529.2 ft
Vertex formed by sides measuring 248 ft and 323.4 ft.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! I have constructed a pentagon with a base of 529.2 ft.=AB SAY The other sides follow clockwise in this order: 57.6 ft=BC, 248 ft=CD, 323.4 ft=DE, and 48.5 ft=EA. How do I find the measure of a perpendicular drawn from..NO ..IT IS TO the base AB to..NO IT IS FROM the opposite vertex D?
Base = 529.2 ft
Vertex formed by sides measuring 248 ft and 323.4 ft.
USING ABOVE NOMENCLATURE.....
TAKE A COMPASS WITH SOME CONVENIENT RADIUS BIG ENOUGH SO THAT WHEN YOU DRAW AN ARC WITH THAT RADIUS KEEPING THE CENTRE AT D,THE ARC CUTS AB OR EXTENDED AB ON EITHER SIDE AT 2 POINTS ...SAY...P AND Q.
NOW DRAW 2 ARCS WITH SAME RADIUS ,KEEPING THE CENTRE AT P AND Q..ON TO THE OTHER SIDE OF AB .LET THE 2 ARCS CUT AT R.JOIN DR.LET DR CUT AB AT Z.NOW DZ IS THE PERPENDICULAR FROM VERTEX...D TO BASE....AB.
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