SOLUTION: I'm sure i can figure this out if you can just tell me how to translate this into a mathematical equation: three-fourths of the students in Math 200 recieved a grade of C on the

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Question 338239: I'm sure i can figure this out if you can just tell me how to translate this into a mathematical equation:
three-fourths of the students in Math 200 recieved a grade of C on their test, and one-fifth recieved an A. if twenty-two more students recieved C's than recieved A's, how many students are in the class?
Thanks!

Found 2 solutions by checkley77, katealdridge:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
3/4x=1/5x+22
3x/4-x/5=22
(3x*5-x*4)/4*5=22
(15x-4x)/20=22 cross multiply.
11x=20*22
11x=440
x=440/11
x=40 ans. for the number of students.
Proof:
3/4*40=1/5*40+22
120/4=40/5+22
30=8+22
30=30

Answer by katealdridge(100) About Me  (Show Source):
You can put this solution on YOUR website!
Let y = the total number of students in Math 200. Let A+=+%281%2F5%29x, C+=%283%2F4%29x. This is essentially a proportion problem. Change the fractions into equivalent ones with common denominators.
A+=+%284%2F20%29x, C+=+%2815%2F20%29x. This leaves another %281%2F20%29x unaccounted for. Let's call that B,(it doesn't really matter). So the grades in the class are in the proportion 4:1:15, (A:B:C)
Whenever you want to solve a proportion problem, take the proportion numbers, multiply each of them by x and add them together:
4x%2B1x%2B15x=20x Now it's time to take into account the next piece of info:22 more students got Cs than As. So we can change the C part of the equation (15x) into 4x+22. Now substitute that into the equation:
4x%2B1x%2B4x%2B22=20x Solve for x.
9x%2B22=20x
22=11x
2=x
Now substitute 2 for x in the equation 4x%2B1x%2B15x=20x. You get 20%2A2=40.
There are 40 students in Math 200.
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