SOLUTION: i don't know how to setup the following word problem:
a pilot flew a jet from city a to city b, a distance of 2500 miles. on the return trip the average speed was 20% faster tha
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a pilot flew a jet from city a to city b, a distance of 2500 miles. on the return trip the average speed was 20% faster tha
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Question 337993: i don't know how to setup the following word problem:
a pilot flew a jet from city a to city b, a distance of 2500 miles. on the return trip the average speed was 20% faster than the outbound speed. The round trip took 9h 10m. what was the speed from city a to city b?
i attempted a table: d=r * t and it didn't work out. Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! find one hour
2500/9 1/6=
2500/55/6=
2500/1*6/55=15000/55 =272.7 mph
x+1.2x=272.7
2.2x=272.7
x=123.97 mph
1.2x=148.76 mph
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