SOLUTION: The problem is cube root 3 * cube root 4. i have come up with 2 square root of 2. The directions say simplify. Can someone please verify if this is correct? Thanks for your help in

Algebra ->  Square-cubic-other-roots -> SOLUTION: The problem is cube root 3 * cube root 4. i have come up with 2 square root of 2. The directions say simplify. Can someone please verify if this is correct? Thanks for your help in      Log On


   

Question 33793: The problem is cube root 3 * cube root 4. i have come up with 2 square root of 2. The directions say simplify. Can someone please verify if this is correct? Thanks for your help in advance.
Found 2 solutions by Nate, AnlytcPhil:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
the cubed root of x is expressed as (x)^(1/3)
(3)^(1/3) * (4)^(1/3)
(12)^(1/3) is your answer (the cubed root of 12)

Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
The problem is cube root 3 * cube root 4. 
i have come up with 2 square root of 2. 
The directions say simplify. Can someone 
please verify if this is correct? 
Thanks for your help in advance.

No, that's wrong.  They are radicals with the same index,
so you simply multiply what's under the radicals.

  _   _      __
³Ö3·³Ö4  = ³Ö12

Edwin
AnlytcPhil@aol.com