SOLUTION: A farmer plans to build a rectangular pen taht is 16 feet long. The area of the pen is 80 square feet. Is 40 feet of fencing enough to fence in the pen?

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Question 337862: A farmer plans to build a rectangular pen taht is 16 feet long. The area of the pen is 80 square feet. Is 40 feet of fencing enough to fence in the pen?
Found 2 solutions by edjones, Edwin McCravy:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Lw=A
16w=40
w=40/16=10/4=5/2
2L+2w=P
2*16 + 2 * 5/2
=32+5
=37
Yes, 40 feet of fencing enough to fence in the pen.
.
Ed

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length be x
Let the width by y

Area = xy = 80
Perimeter = 2x + 2y < 40 

So we have 

system%28xy=80%2C2x%2B2y%3C=40%29

Solve the equation for y y=80%2Fx

Substitute in the inequality

2x+%2B+2%2880%2Fx%29+%3C=40

2x+%2B+160%2Fx+%3C=+40

Since x is positive we can multiply through by x without
reversing the inequality symbol

2x%5E2%2B160+%3C=+40x

2x%5E2-40x%2B160%3C=0

Divide through by 2

x%5E2-20x%2B80%3C=0

Find the zeros of the expression on the left.

It doesn't factor, so:

 x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

 x+=+%28-%28-20%29+%2B-+sqrt%28%28-20%29%5E2-4%2A1%2A80+%29%29%2F%282%2A1%29+

 x+=+%2820+%2B-+sqrt%28400-320%29%29%2F2+

 x+=+%2820+%2B-+sqrt%2880%29%29%2F2+

x+=+%2820+%2B-+sqrt%2816%2A5%29%29%2F2+

x+=+%2820+%2B-+4sqrt%285%29%29%2F2+

x+=+%284%285+%2B-+sqrt%285%29%29%29%2F2+

x+=+2%285+%2B-+sqrt%285%29%29+

The two zeros are approximately 5.5 and 14.5

So we mark those two points on a number line:


number_line%28+700%2C+-1%2C20%2C+2%285%2Bsqrt%285%29%29%2C+2%285-sqrt%285%29%29+%29

So we test a point is the region left of 5.5, say 5, in

the region left of the 5 in the inequality:

x%5E2-20x%2B80%3C=0
5%5E2-20%285%29%2B80%3C=0
25-100%2B80%3C=0
5%3C=0

That's false so we do not shade the part of the number line
left of the green point.

Next we test a point is the region between 5.5 and 14.5, say 6, in
the inequality:

x%5E2-20x%2B80%3C=0
6%5E2-20%286%29%2B80%3C=0
36-120%2B80%3C=0
-4%3C=0

That's true so we shade the part of the number line between the
green and red points:



Now we test a point is the region right of 14.5, say 15, in

the region left of the 5 in the inequality:

x%5E2-20x%2B80%3C=0
15%5E2-20%2815%29%2B80%3C=0
225-300%2B80%3C=0
5%3C=0

That's false so we do not shade the part of the number line
right of the red point.

So the solution set for the inequality in interval notation is

solution_set%282%285%2Bsqrt%285%29%29%2C+2%285-sqrt%285%29%29+%29

So yes we can make the length any value  of x between those two
values, and the width y=80%2Fx, and 40 will be enough fencing.

Edwin