SOLUTION: determine two consecutive positive integers whose squares sum to 925

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Question 337808: determine two consecutive positive integers whose squares sum to 925
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint: "two consecutive positive integers" means that we have the numbers 'x' and 'x+1'. So if we want to "determine two consecutive positive integers whose squares sum to 925", then we need to solve x%5E2%2B%28x%2B1%29%5E2=925

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(925/2) =~ 21.5
--> 21 and 22
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