Question 33772: Floyd has 16 coins in pennies, nickels, and dimes. The number of dimes is equal to the sum of the number of pennies and number of nickels. If the total value of the coins is $1.08, how many of each kind does he have?
Answer by Paul(988)   (Show Source):
You can put this solution on YOUR website! Let the number of nickels be x
Let the number of pennies be y
Let the number of dimes be z
Now z=x+y
FIrst equation:
z+x+y=16
Subsittue for z:
x+y+x+y=16
y=8-x (subsitution)
Second Equation:
10(z)+(y)+5(x)=108
Subsittue for z:
10(x+y)+y+5x=108
10x+10y+y+5x=108
Subsitute for y:
15x+11(8-x)=108
15x+88-11x=108
4x=20
x=5
y=8-5
y=3
z=3+5
z=8
Hence, there are 8 dimes, 3 pennies and 5 nickels.
Paul.
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