SOLUTION: how do you right (16x^2-96x+9y^2+18y=-9) in standard form

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: how do you right (16x^2-96x+9y^2+18y=-9) in standard form      Log On


   

Question 337573: how do you right (16x^2-96x+9y^2+18y=-9) in standard form
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
16x%5E2-96x%2B9y%5E2%2B18y=-9
16%28x%5E2-6x%29%2B9%28y%5E2%2B2y%29=-9
16%28x%5E2-6x%2B9%29%2B9%28y%5E2%2B2y%2B1%29=-9%2B16%289%29%2B9%281%29
16%28x-3%29%5E2%2B9%28y%2B1%29%5E2=144
highlight%28%28x-3%29%5E2%2F9%2B%28y%2B1%29%5E2%2F16=1%29