SOLUTION: rays PQ and QR are perpendicular. Point s lies in the interior of pqr. if pqs =4+7a and sqr = 9+4a, find pqs and sqr

Algebra ->  Angles -> SOLUTION: rays PQ and QR are perpendicular. Point s lies in the interior of pqr. if pqs =4+7a and sqr = 9+4a, find pqs and sqr      Log On


   

Question 337498: rays PQ and QR are perpendicular. Point s lies in the interior of pqr. if pqs =4+7a and sqr = 9+4a, find pqs and sqr
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
PQS%2BSQR=90
4%2B7a%2B9%2B4a=90
11a%2B13=90
11a=77
a=7
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PQS=4%2B7a=4%2B49=53degrees
SQR=9%2B4a=9%2B28=37degrees