SOLUTION: How do I solve the equation, {{{2/(x+4) +1}}} = {{{12/(x^2+9x+20)}}} ? 2/(X+4) + 1 = 12/(X^2+9X+20) 1={12/{(X+5)(X+4)} *(X+4)/2] 1=[{12 (X+4) }/{2(X+4)(X+5)}] … (

Algebra ->  Equations -> SOLUTION: How do I solve the equation, {{{2/(x+4) +1}}} = {{{12/(x^2+9x+20)}}} ? 2/(X+4) + 1 = 12/(X^2+9X+20) 1={12/{(X+5)(X+4)} *(X+4)/2] 1=[{12 (X+4) }/{2(X+4)(X+5)}] … (      Log On


   

Question 337477: How do I solve the equation, 2%2F%28x%2B4%29+%2B1 = 12%2F%28x%5E2%2B9x%2B20%29 ?
2/(X+4) + 1 = 12/(X^2+9X+20)
1={12/{(X+5)(X+4)} *(X+4)/2]
1=[{12 (X+4) }/{2(X+4)(X+5)}] …
(X+4) IS CANCEL AND 12/2 IS 6
1*(X+5)=[6(1/(X+5)) *(X+5)] MULTIPLY THE INVERSE
1*(X+5) = 6 SUBTRACT BOTH SIDES WITH 5
X+5-5 = 6-5
X=1
Answer by chiexpert(48) About Me  (Show Source):
You can put this solution on YOUR website!
2/(X+4) + 1 = 12/(X^2+9X+20)
1={12/{(X+5)(X+4)} *(X+4)/2]
1=[{12 (X+4) }/{2(X+4)(X+5)}] …
(X+4) IS CANCEL AND 12/2 IS 6
1*(X+5)=[6(1/(X+5)) *(X+5)] MULTIPLY THE INVERSE
1*(X+5) = 6 SUBTRACT BOTH SIDES WITH 5
X+5-5 = 6-5
X=1