SOLUTION: Find an equation in standard form of the line through the point (3, -5) that is perpendicular to the line with equation x + 3y = 6

Algebra ->  Linear-equations -> SOLUTION: Find an equation in standard form of the line through the point (3, -5) that is perpendicular to the line with equation x + 3y = 6      Log On


   

Question 337196: Find an equation in standard form of the line through the point (3, -5) that is perpendicular to the line with equation x + 3y = 6
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to slope intercept form,
+x+%2B+3y+=+6
3y=-x%2B6
y=-x%2F3%2B2
Perpendicular lines have slopes that are negative reciprocals,
m1%2Am2=-1
-%281%2F3%29%2Am2=-1
m2=3
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y=3x%2Bb
Use the point to solve for b.
-5=3%283%29%2Bb
b=-14
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highlight%28y=3x-14%29
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