SOLUTION: In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line l at (0, p) and (5, t). What is the greatest possible value of the slope of l?

Algebra ->  Linear-equations -> SOLUTION: In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line l at (0, p) and (5, t). What is the greatest possible value of the slope of l?       Log On


   

Question 337093: In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line l at
(0, p) and (5, t). What is the greatest possible value of the slope of l?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line l at
(0, p) and (5, t). What is the greatest possible value of the slope of l?
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Substitute each point into the equation to get two equations in p and t.
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p = 0^2-4
t = 5^2-4
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p = -4
t = 21
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You now have two points: (0,-4) and 5,21)
slope of line L = (21--4)/(-4-0) = 25/-4 = -4/25
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Cheers,
Stan H.