SOLUTION: Two consecutive vertices of a parallelogram are (3,-3) and (0,2).If their diagonals meet at the origin find the other two vertices.

Algebra ->  Parallelograms -> SOLUTION: Two consecutive vertices of a parallelogram are (3,-3) and (0,2).If their diagonals meet at the origin find the other two vertices.      Log On


   

Question 337067: Two consecutive vertices of a parallelogram are (3,-3) and (0,2).If their diagonals meet at the origin find the other two vertices.
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

The line segment drawn is the right side of the parallelogram.
Since the diagonals must intersect at the origin, and since
the diagonals of a parallelogram bisect each other, the
green line below is one-half of one of the diagonals:

So we draw in the other half of that diagonal which extends
down to (0,-2):

Therefore (0,-2) is the lower left vertex of the
parallelogram. So we can draw in the bottom side of the
parallelogram, as well as one-half of the other diagonal:

Notice that the lower left vertex is 3 units left of
and 1 unit above the lower right vertex. Therefore
the upper left vertex must be 3 units left of and 1 unit
above the upper right vertex, which puts it at (-3,3).
So now we can finish drawing the parallelogram, and the
rest of the other diagonal: