SOLUTION: I need help solving the following equation for 0(<=) X (<=)2pi 2sinXcosX= (sqrt 2)cosX

Algebra ->  Trigonometry-basics -> SOLUTION: I need help solving the following equation for 0(<=) X (<=)2pi 2sinXcosX= (sqrt 2)cosX      Log On


   



Question 337033: I need help solving the following equation for 0(<=) X (<=)2pi
2sinXcosX= (sqrt 2)cosX

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2sin%28X%29cos%28X%29=+sqrt%282%29cos%28X%29
2sin%28X%29=+sqrt%282%29
sin%28X%29=+sqrt%282%29%2F2
.
.
.
What are the two values of X that have this value for sin%28X%29?