SOLUTION: If Sara can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them working together to paint the same house.

Algebra ->  Rate-of-work-word-problems -> SOLUTION: If Sara can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them working together to paint the same house.      Log On


   



Question 337: If Sara can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them working together to paint the same house.
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
If Sara can paint a house in 4 hours, and John can paint the same house in 6
hours, how long will it take for both of them working together to paint the
same house.
'
Let x = the number of hours it will take both of them working together.
`
>>...Sara can paint a house in 4 hours...<<
`
Translation: In one hour she can paint 1/4th of the house, so
in x hours she can paint x/4ths of the house. That is to say, the fraction of
the house that she paints in those x-hours is x/4.
`
>>...John can paint the same house in 6 hours...<<
`
Translation: In one hour she can paint 1/6th of the house, so
in x hours she can paint x/6ths of the house. That is to say, the fraction of
the house that he paints in those x-hours is x/6.
`
The fraction of the house that Sara paints +
` the part of the house that John paints =
` 1 house
` ` ` ` ` ` ` ` ` ` ` ` `x/4 + x/6 = 1
Multiply thru by LCD = 12 to clear of fractions
` ` ` ` ` ` ` ` ` `12·x/4 + 12·x/6 = 12·1
` ` ` ` ` ` ` ` ` ` ` ` ` `3x + 2x = 12
` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` 5x = 12
` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` `x = 12/5 = 2 2/5 hours or 2 hours 24 minutes
Edwin