SOLUTION: Can you please help me factor this polynomial? 8x^2 + 16x +12 thank you!

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Question 336804: Can you please help me factor this polynomial?
8x^2 + 16x +12 thank you!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

8x%5E2%2B16x%2B12 Start with the given expression


4%282x%5E2%2B4x%2B3%29 Factor out the GCF 4


Now let's focus on the inner expression 2x%5E2%2B4x%2B3




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Looking at 2x%5E2%2B4x%2B3 we can see that the first term is 2x%5E2 and the last term is 3 where the coefficients are 2 and 3 respectively.

Now multiply the first coefficient 2 and the last coefficient 3 to get 6. Now what two numbers multiply to 6 and add to the middle coefficient 4? Let's list all of the factors of 6:



Factors of 6:
1,2,3,6

-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 6
1*6
2*3
(-1)*(-6)
(-2)*(-3)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4

First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5

None of these pairs of factors add to 4. So the expression 2x%5E2%2B4x%2B3 cannot be factored

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Answer:
So 8x%5E2%2B16x%2B12 factors to 4%282x%5E2%2B4x%2B3%29

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my website.

Jim