SOLUTION: I need to write the slope-intercept inequality for this graph that has the points (0,1) and (3,-1). I just don't get how to do it, I've trying to figure it out for hours and its ov

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Question 336793: I need to write the slope-intercept inequality for this graph that has the points (0,1) and (3,-1). I just don't get how to do it, I've trying to figure it out for hours and its overwhelming.
Found 2 solutions by checkley77, solver91311:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
(0,1) and (3,-1)
Slope=(y2-y1)/(x2-x1)
Slope=(-1-1)/3-0)
Slope(m)=-2/3
y=mx+b
Replace x*y by (0,1)
1=2/3*0+b
1=0+b
b=1 ans. for the y intercept.
y=-2/3x+1
y=1
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -2x/3 +1).

Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

For what graph? Are we just supposed to guess?

Use the two given points with the two-point form of an equation of a line to write the equation of the boundary line.

where and are the coordinates of the given points.

Then do whatever you need to do to solve for in terms of everything else. That is to say, rearrange your equation into slope intercept form,

Next pick a point out of the shaded area on your graph that is NOT on the boundary line. Substitute the and coordinate values from the point you picked into the equation. Once you have done all the arithmetic, remove the equals sign from your equation and replace it with the appropriate inequality sign, that is make it point the way that makes the statement true. Then go back and look at your graph. If the boundary line is solid, make your inequality include "or equals" If it is dashed, then make your inequality strict.

John

My calculator said it, I believe it, that settles it