Question 336141: Solve each equation in the complex number system?
x^2-6x+13=0
The answer is {3-2i , 3+2i}
Just don't know how to get there?
Thanks,
Isabel Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Solve each equation in the complex number system?
x^2-6x+13=0
a = 1 ; b = -6 ; c = 13
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Use the quadratic formula:
x = [-b +- sqrt(b^2-4ac)]/(2a)
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x = [6 +- sqrt(36-4*1*13)]/(2)
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x = [6 +- sqrt(-16)]/2
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x = [6 +- 4i]/2
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x = 3+2i or x = 3-2i
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Cheers,
Stan H.
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