SOLUTION: A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is
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Question 336070: A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is 2/3? Explain Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is 2/3?
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Let the number of green skittles added be "x".
Total # of skittles in the bag = 5+x + 3 +2 + 6 = 16+x
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P(selecting a green skittle) = (x+5)/(x+16) = 2/3
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Solve for "x:
Cross-multiply to get:
3(x+5) = 2(x+16)
3x+15 = 2x + 32
x = 17 (# of green skittles added)
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Cheers,
Stan H.
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