SOLUTION: Find two consecutive even integers such that twelve times the first equals eight times the second

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Question 335993: Find two consecutive even integers such that twelve times the first equals eight times the second
Answer by Fombitz(32388) About Me  (Show Source):
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Let the integers be N+and N%2B2
12N=8%28N%2B2%29
12N=8N%2B16
4N=16
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N=4
N%2B2=6