SOLUTION: Directions: Graph the line that satisfies each set of conditions. Problem: Passes through (-3, -1), parallel to a line whose slope is -1 I am pretty sure you use the "point-slo

Algebra ->  Linear-equations -> SOLUTION: Directions: Graph the line that satisfies each set of conditions. Problem: Passes through (-3, -1), parallel to a line whose slope is -1 I am pretty sure you use the "point-slo      Log On


   

Question 335976: Directions: Graph the line that satisfies each set of conditions.
Problem: Passes through (-3, -1), parallel to a line whose slope is -1
I am pretty sure you use the "point-slope" formula on this problem, but I'm still have a bit of trouble. Thank you.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel lines have equal slopes. So this line has a slope of -1.


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y--1=-1%28x--3%29 Plug in m=-1, x%5B1%5D=-3, and y%5B1%5D=-1


y%2B1=-1%28x--3%29 Rewrite y--1 as y%2B1


y%2B1=-1%28x%2B3%29 Rewrite x--3 as x%2B3


y%2B1=-1x%2B%28-1%29%283%29 Distribute -1


y%2B1=-1x-3 Multiply -1 and 3 to get -3


y=-1x-3-1 Subtract 1 from both sides to isolate y


y=-1x-4 Combine like terms -3 and -1 to get -4


y=-x-4 Simplify.


So the equation is y=-x-4


Now graph the line to get


Graph of the parallel line y=-x-4 (green) through the point .



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Jim