SOLUTION: Directions: Graph the line that satisfies each set of conditions. Problem: Passes through (3, 0), perpendicular to a line whose slope is 3/2 I think you use the "point slope" f

Algebra ->  Linear-equations -> SOLUTION: Directions: Graph the line that satisfies each set of conditions. Problem: Passes through (3, 0), perpendicular to a line whose slope is 3/2 I think you use the "point slope" f      Log On


   

Question 335970: Directions: Graph the line that satisfies each set of conditions.
Problem: Passes through (3, 0), perpendicular to a line whose slope is 3/2
I think you use the "point slope" formula on this one, but I'm not sure. When I tried it, it came out all wrong, so it'd be nice for anyone to help. Thank you!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Any line that is perpendicular to a line with a slope of 3%2F2 will have a slope of -2%2F3 (flip the fraction and change the sign)


So our perpendicular line has a slope of -2%2F3 and goes through the point (3, 0)


Now we can use the point slope formula to find the equation of the line. The point slope formula is:


y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point


y-0=%28-2%2F3%29%28x-3%29 Plug in m=-2%2F3, x%5B1%5D=3, and y%5B1%5D=0


y=%28-2%2F3%29%28x-3%29 Simplify.


y=%28-2%2F3%29x%2B%28-2%2F3%29%28-3%29 Distribute -2%2F3


y=%28-2%2F3%29x%2B2 Multiply -2%2F3 and -3 to get 2


So the equation of the line is y=%28-2%2F3%29x%2B2


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my website.

Jim