SOLUTION: How can i solve by completing the square? I know a bit how but i just need some help!
X^2-X-1=0
X^2-X=1
X^2-x/2=1/2
X^2-x/2+(-1/4)^2=1/2+(-1/4)^2
I get lost here can
Algebra ->
Square-cubic-other-roots
-> SOLUTION: How can i solve by completing the square? I know a bit how but i just need some help!
X^2-X-1=0
X^2-X=1
X^2-x/2=1/2
X^2-x/2+(-1/4)^2=1/2+(-1/4)^2
I get lost here can
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Question 33597: How can i solve by completing the square? I know a bit how but i just need some help!
X^2-X-1=0
X^2-X=1
X^2-x/2=1/2
X^2-x/2+(-1/4)^2=1/2+(-1/4)^2
I get lost here can some one help me solve or make any corrections THNX! Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! I will copy and correct your problem:
X^2-X-1=0
X^2-X=1 add one
(x-(1/2))^2=1+(1/4) take half of 1 and square that to add to other side
(x-(1/2))^2=(5/4) simplify
x-(1/2)=+ or -((5)^(1/2))/2 square root to get a positive and negative
x=(1/2)+((5)^(1/2))/2) or x=(1/2)-((5)^(1/2))/2) and (1/2)
your answer:
x=(1/2)+((5)^(1/2))/2) or x=(1/2)-((5)^(1/2))/2)
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