SOLUTION: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step.
x(x+2)= 5(x+
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step.
x(x+2)= 5(x+
Log On
Question 335730: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step.
x(x+2)= 5(x+x+2)-23
x^2+2x=5x+5x+10-23
x^2+2x=10x-13
x^2-8x-13
(