SOLUTION: If Peg traveled 10 miles in 2 hours and Linda traveled twice as far in half the time, what was Linda’s average speed, in miles per hour? (A) 5 (B) 10 (C) 20 (D) 30 (E) 40

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Question 335607: If Peg traveled 10 miles in 2 hours and Linda traveled twice as far in half the time, what was Linda’s average speed, in miles per hour?
(A) 5 (B) 10 (C) 20 (D) 30 (E) 40
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Peg = 10/2 = 5mph
Linda = twice as far or 2 x 10 divide by 1/2 of 2 or 20/1 = 20
CHOICE C.