SOLUTION: One number is 9 times a first number. A third number is 100 times more than the first number. If the sum of the three numbers is 683, find the numbers

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Question 335511: One number is 9 times a first number. A third number is 100 times more than the first number. If the sum of the three numbers is 683, find the numbers
Found 2 solutions by Fombitz, nyc_function:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let's call the numbers A,B and C.
B=9A
C=100A
A%2BB%2BC=683
Substitute,
A%2B9A%2B100A=683
110A=683
highlight%28A=683%2F110%29
.
.
B=9%28683%2F110%29
highlight%28B=6147%2F110%29
.
.
C=100%28683%2F110%29
highlight%28C=6830%2F11%29

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = first number
Let 9x = second number
Let 100 + x = third number
x + 9x + 100 + x = 683
Can you take it from here?