SOLUTION: The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and the width, you double the perimeter. find the length and width of the original

Algebra ->  Rectangles -> SOLUTION: The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and the width, you double the perimeter. find the length and width of the original      Log On


   

Question 335472: The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and the width, you double the perimeter. find the length and width of the original rectangle.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
For a rectangle,
P=2L%2B2W
W=L-12
P1=2L%2B2%28L-12%29
P1=2L%2B2L-24
P1=4L-24
.
.
.
P2=4%28L%2B30%29-24
P2=4L%2B120-24
P2=4L%2B96
.
.
.
P2=2%2AP1
4L%2B96=2%284L-24%29
4L%2B96=8L-48
-4L=-144
highlight%28L=36%29
W=36-12
highlight%28W=24%29
.
.
.
The original rectangle is 24 x 36.