SOLUTION: How many whole numbers are there, such that if its digits are reversed and then subtracted from the original number, the result is 198?

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Question 335299: How many whole numbers are there, such that if its digits are reversed and then subtracted from the original number, the result is 198?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let the original number be ABC, where the numerical value is 100%2AA%2B10%2AB%2BC.
The reverse number would be CBA or numerically 100%2AC%2B10%2AB%2BA.
.
.
100A%2B10B%2BC-100C-10B-A=99A-99C=198
A-C=2
A=C%2B2
A, B, and C can take on values from 0 to 9.
For each value of B, there are 8 A,C values.
0B2
1B3
2B4
3B5
4B6
5B7
6B8
7B9
So there would be 10%2A8 or 80 number pairs that meet this criteria.
If leading zeros aren't allowed (like 012/210), then reduce the B values allowed by 1, and then 9%2A8 or 72 number pairs are allowed.