SOLUTION: (Revision)solve for x, y and z making each statement true:
y > x
z < y
x < 0
x / z = -z
x / y = z
z / 2 and z / 3 are integers
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-> SOLUTION: (Revision)solve for x, y and z making each statement true:
y > x
z < y
x < 0
x / z = -z
x / y = z
z / 2 and z / 3 are integers
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Question 335260: (Revision)solve for x, y and z making each statement true:
y > x
z < y
x < 0
x / z = -z
x / y = z
z / 2 and z / 3 are integers Answer by solver91311(24713) (Show Source):
From the fact that x is negative and the quotient of x and y is z, you can deduce that not all three numbers are negative, hence y has to be positive because it is greater than each of the other two, and z must be negative because a negative (x) divided by a positive (y) must be negative.
From the fact that z/2 and z/3 are integers, and that z is negative, you can deduce that z must be -6 or an integer multiple of -6.
So let z = -6n where n is an natural number. Then from x/z = -z, you can deduce that x = -36n^2. And then from x/y = z you can determine that y = 6n.
Solution set:
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All statements true, answer checks.
John
My calculator said it, I believe it, that settles it
