Question 334908: Find the equation of the parabola with vertex at (−2, 2) and directrix at y = 4
Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! Since the directrix is horizontal, then the general term of parabola is
(x-α)^2 = 4p(y-β) vertex (α,β) = (-2,2)
(x+2)^2 = 4p(y-2)
p is the distance from vertex to directrix = 2
The equation of parabola : (x+2)^2 = 8(y-2)
|
|
|