SOLUTION: Solve by Factoring:
x^2-9x=-20
x^2-9x+20=0
x^2-4x-5x+20=0
x(x-4)+(-5)(x-4)=0
(x-5)(x-4)=0
(x-5) or (x-4)
x=5 or x=4
Is this Correct? Thank you
Algebra ->
Absolute-value
-> SOLUTION: Solve by Factoring:
x^2-9x=-20
x^2-9x+20=0
x^2-4x-5x+20=0
x(x-4)+(-5)(x-4)=0
(x-5)(x-4)=0
(x-5) or (x-4)
x=5 or x=4
Is this Correct? Thank you
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Question 33489: Solve by Factoring:
x^2-9x=-20
x^2-9x+20=0
x^2-4x-5x+20=0
x(x-4)+(-5)(x-4)=0
(x-5)(x-4)=0
(x-5) or (x-4)
x=5 or x=4
Is this Correct? Thank you Answer by mukhopadhyay(490) (Show Source):
You can put this solution on YOUR website! It is mostly corect
x^2-9x=-20
x^2-9x+20=0
x^2-4x-5x+20=0
x(x-4)+(-5)(x-4)=0
(x-5)(x-4)=0
(x-5)=0 or (x-4)=0............(This is where you made a small mistake)
x=5 or x=4