SOLUTION: Solve using the substitution method {{{4x+3y=7}}} {{{2x-y=1}}} I could use some help on this on please. thank you

Algebra ->  Linear-equations -> SOLUTION: Solve using the substitution method {{{4x+3y=7}}} {{{2x-y=1}}} I could use some help on this on please. thank you       Log On


   

Question 334716: Solve using the substitution method
4x%2B3y=7
2x-y=1
I could use some help on this on please.
thank you
Found 2 solutions by stanbon, checkley77:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
4x+3y=7
2x-y=1
-----------
Solve 2nd for "y":
y = 2x-1
----
Substitute for "y" in 1st and solve for "x":
4x+3(2x-1) = 7
4x+6x-3 = 7
10x = 10
x = 1
-------
Substitute into y = 2x-1 to solve for "y":
y = 2*1-1 = 1
=================
Cheers,
Stan H
================

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
4x%2B3y=7
2x-y=1
y=2x-1
replace y in the first equation by (2x-1) & solve for x.
4x+3(2x-1)=7
4x+6x-3=7
10x=7+3
10x=10
x=1 ans.
y=2*1-1
y=2-1
y=1 ans.
Proof:
4*1+3*1=7
4+3=7
7=7