SOLUTION: the sum of two integers is ten. three times the larger integer is three less than eight times the smaller interger. Find the intergers. i know the answer is 3 and 7 but teacher wa

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Question 3346: the sum of two integers is ten. three times the larger integer is three less than eight times the smaller interger. Find the intergers. i know the answer is 3 and 7 but teacher wants the algebraic expression and solution worked out and i can't do that
Answer by drglass(89) About Me  (Show Source):
You can put this solution on YOUR website!
To solve problems like this start by giving names to the integers. Call the bigger integer x and the smaller one y. Now, the problem tells us that the sum of x and y is 10. We can write this mathematically as:

x+%2B+y+=+10

The problem also tells us that "three times the larger integer is three less then eight times the smaller integer." Let's break this up a little, three times the larger means three times x 3x (x is the larger, right?). Next we are told that 3x is three less than eight times the smaller. Well, eight times the smaller is 8y and three less than 8y is 8y+-+3. The problem says 3x is 8y+-+3 or, 3x+=+8y+-+3.

This gives us two equations:


  1. x+%2B+y+=+10 and

  2. 3x+=+8y+-+3


If we subtract y from both sides of the first equation, we get x+=+10+-+y

Now substitute x in the second equation with 10+-+y and we get3%2810+-+y%29+=+8y+-+3

multiply 3 into the first part of the equation to get 30+-+3y+=+8y+-+3

add 3 to both sides to get 33+-+3y+=+8y

add 3y to both sides to get 33+=+11y

finally, divide both sides by 11 to get y+=+3.

Since we know x+%2B+3+=+10, we know x+=+7