SOLUTION: In the vicinity of a bonfire, the temperature T in degree celsius at a distance of x meters from the center of the fire was given by: T=600000/(x^2+300) At what range of dist

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Question 334413: In the vicinity of a bonfire, the temperature T in degree celsius at a distance of x meters from the center of the fire was given by:
T=600000/(x^2+300)
At what range of distances from the fire's center was the temperature less than 500 degree celsius?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
T=600000%2F%28x%5E2%2B300%29
x%5E2%2B300+=+600000%2FT
x%5E2+=+%28600000%2FT%29+-+300
x+=+sqrt%28%28600000%2FT%29+-+300%29
What distance is the temperature 500?
x+=+sqrt%28%28600000%2F500%29+-+300%29
x+=+sqrt%281200+-+300%29
x+=+sqrt%28900%29
x+=+30
So at 30 meters the temperature is 500.
Any distance greater than 30m will result in a temperature less than 500