SOLUTION: I am wondering if I figured this out right. Could you please help me with this?
I must create a binomial representing the length in this problem. A rectangle x centimeters wid
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I must create a binomial representing the length in this problem. A rectangle x centimeters wid
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Question 334218: I am wondering if I figured this out right. Could you please help me with this?
I must create a binomial representing the length in this problem. A rectangle x centimeters wide w/an area of x^2+50x. My answer is L=50x-x^2. Is that correct? If not, could you please walk me through the procedure?
Thank you, kindly. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A rectangle x centimeters wide w/an area of x^2+50x
Area = L * W
W = x
x^2 + 50x = W * L = x*L
L = Area/W = (x^2 + 50x)/x
L = x + 50
