SOLUTION: A bag contains 3 red balls and 5 blue balls. One ball is taken at random, its colour noted, and put back into the bag. A second ball is taken at random , and again its colour is no

Algebra ->  Probability-and-statistics -> SOLUTION: A bag contains 3 red balls and 5 blue balls. One ball is taken at random, its colour noted, and put back into the bag. A second ball is taken at random , and again its colour is no      Log On


   



Question 334118: A bag contains 3 red balls and 5 blue balls. One ball is taken at random, its colour noted, and put back into the bag. A second ball is taken at random , and again its colour is noted.
What is the probability of obtaining two balls of different colours?


Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

P(different colors) = P[(red first AND blue second) OR (blue first AND red second)]

"AND" means MULTIPLY and "OR" means ADD, so that equals

 P[red first] x P[blue second] + P[blue first] x P[red second] =

3%2F8x5%2F8%22%22%2B%22%225%2F8x3%2F8 =

15%2F64%2B15%2F64%22%22=%22%2230%2F64%22%22=%22%2215%2F32

Edwin