Question 334111: How many distinguishable permutations of letters are possible in the word COMMITTEE
Must show work Found 2 solutions by stanbon, jrfrunner:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many distinguishable permutations of letters are possible in the word COMMITTEE
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9!/(2!*2!*2!) = 9!/8 = 45360 permutations.
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Cheers,
Stan H.
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You can put this solution on YOUR website! the word COMMITTEE has 9 letters so 9!= permutation of that word,b ut...
since the letters M, T and E are repeated each twice, there will be words that are indestinguishable from each othe because one M is not different from the other M, and same for the T and E.
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So we need to back these words out.
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answer: 9!/(2!*2!*2!)= 45360
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