Question 333861: let log k 2=11/9. find log 8 k.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! let log k 2=11/9. find log 8 k.
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logk(2)=11/9
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k^(11/9) = 2
k = 2^(9/11)
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log8(k) = [log(k)]/[log(8)]
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= log(2^(9/11))/log(8)
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Take the log base 2 of numerator and denominator to get:
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= (9/11)/3
= 3/11
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Cheers,
Stan H.
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